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Action is regarding arrests in C++, so we have studied about variables, data types and also we have

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looked into control statements and patient statements support like when we are declaring a simple single

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immediately, it will really having a provision to store one value in that meeting for.

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So if I'm declaring.

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Let me get the panel so for you.

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OK, so if I'm declaring E!

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Equal to 10, then my baby will be having a provision to hold only one value, they're distant if I'm

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giving equal opportunity at some point of time.

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This existing 10 will be replaced with 20 and it will store that value.

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So if I want to store 10 different values, I will need 10 different variables.

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State if I'm naming my baby was ABC to like, like like that.

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If I'm having 10 different values, I will need to use 10 different variables.

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So this is not a good practice, so in order to do store similar kind of values consecutively within

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same name, I will be having our day best picture on a provision in the C++ part of this.

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So why does it not a collection of elements of similar database in which the elements can be unique

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and located in separate memory locations?

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So you can see one array over here.

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This is an example for anybody.

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Having the name of that is violence, but the same are again stored.

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Minivan use it savvy thousand to three point four seven fifty.

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All the values that started in this city, but in different locations, memory locations, different

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parts in the computer memory.

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But what is the case about is it will always use or stored away neighbors in consecutive memory locations

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in nearby many locations.

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So how we can create in order, we can create an array of new data, right, by specifying the data

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type, then really, but tonight, then size of that.

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So here is an example int array of 20.

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It will create array card array, bit trendy card and security memory locations in memory with the Endesa.

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Similarly, I have created one it floor balance of five.

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This is next Saturday here.

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Like Flot.

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This will be a floating point store gallery that any will be balance, and it can be having five memory

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locations listed in that computer memory.

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So here you can see five memory locations all in and that name is balance.

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So the first element of this Iris thousand second element is 2.0, the third item in these three 3.4.

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For them in the seven and.

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So instead of in this state.

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Right.

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So.

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Even just declaring an error, there would be no value, so here it will be like blind got a no value.

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So all the values in this will be nothing but how I can insert this value that is next publicly.

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See, here is the way we can insert the values into adding.

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So the senior position of this added balance can be accessed by using the statement balance of zero,

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then to give that value.

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You can use assignment equal to and then put thousand.

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So then the thousand will be coming over here.

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Similarly, to get the value of the second part of that.

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You can use balance of one.

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So I was hearing that starts at zero, that that will be one blind.

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You have to remember it stocks one zero.

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Then it moves forward.

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So if I want to get the first element, it should be balance of the second element balance of one.

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OK.

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Similarly, balance of N minus one.

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So I have I saved all the balance, another easily assigning all the values at once.

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That's one more way that's shown over here, like flood balance of five equal to zero value lot faster

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value, second value, third value for time.

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That means by values that all these statements this these doorways are similar.

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It will both give you an array like this.

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OK.

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No, we have it time for our demo session.

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We can go to C++ program and see how what I sort of used in C++.

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So we had in the program.

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Let's see.

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So here you can see I have declared one today, which is again, these are bank card numbers.

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Then I am asking the user to give final numbers, which is which is actually I'm going to put pen.

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This might my adding numbers.

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I want to get final most from the user and then I have to store that fine.

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I'm listening to my body.

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OK.

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God numbers.

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So why we are losing for.

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Because I want to get the numbers right, so I am using it for law and specifying that index of that

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value, so I start from zero, which means numbers of I hear and I have numbers of eight between us.

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Fastest numbers of zero seen and asking for that value, right?

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So it will give that.

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So first time, this will be no worse off.

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Zero.

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So whatever number you set us ending, it will be going to that zero.

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The position of the.

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Then I'm going to increment the value, so it will be a plus plus or I equals a plus one.

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This is the shorthand for it, so it will be one.

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Then I'm going to check the condition.

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So it's one less than five.

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Again, no cell.

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So no myself one will be asked and I was told that value in the same number of one.

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Similarly, this will repeat five times.

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Right?

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Zero one two three four.

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And on each execution of this follow, I would get the position right.

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I will get the numbers on each portion of that.

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Now they will similarly for branding it instead of seeing the rosy sealed and giving some space.

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Let's see how this program will look like.

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I think you will you go understanding of this program.

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So let us by executing this program first.

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Before that, I need to compile that.

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So D-plus plus plus I race.

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Dot CPB program is right.

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No, it's not slash, you know, to get the most.

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And the final exam leaving that final.

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So now it's on to see, you know what position, so it will be asking tomorrow.

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That is fascinating, but I will be giving it also here.

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I will be giving it.

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Go ahead.

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Next.

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No.

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56.

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Next, no contract next, No.

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21 next.

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No.

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40 and giving Lee final boss so one time the slope Mexico to Mexico, to Mexico down for time fighting

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executed like this.

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Now I will be pressing and see all the.

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But I haven't done that.

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Display 12:46, 120 140.

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Because I'm printing miry numbers over here, which means that all the numbers are having endured here

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are stored in the record numbers of eight and 12 are stored in numbers of one nine.

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56 was stored in numbers of two zero numbers of zero.

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Number of solid numbers of two numbers of three numbers of four.

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Likewise have stored all the numbers.

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And here, by using the sealed statement, I have navigated using the hollow for each gentlemen of that

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eight and a half printer.

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So how will you gain access to each and every individual element?

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Using follow is what we have discussed in particular program, although you have understood that.

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Do let me know in the session comments if you have any kind of doubts over.