0 1 00:00:00,550 --> 00:00:08,560 Now in the last lesson we looked at how to update records in our tables and we looked at the SQL 1 2 00:00:08,650 --> 00:00:10,210 UPDATE statement. 2 3 00:00:10,240 --> 00:00:15,610 Now in this lesson we're going to look at the last letter of CRUD which is DELETE. 3 4 00:00:15,610 --> 00:00:24,460 And if we wanted to delete records then we can simply write DELETE FROM table name where something meets 4 5 00:00:24,490 --> 00:00:26,950 a certain condition. 5 6 00:00:26,960 --> 00:00:33,590 So for example if I want to delete my record of my pencil say if I no longer sell pencils anymore in 6 7 00:00:33,590 --> 00:00:47,030 my shop then I can simply say DELETE FROM products table where the name is equal to pencil or what would 7 8 00:00:47,030 --> 00:00:53,410 be better is if I actually use its id, where id is equal to 2. Now 8 9 00:00:53,430 --> 00:01:00,500 again be careful that you don't run the statement without a WHERE statement because that will delete 9 10 00:01:00,860 --> 00:01:05,870 everything in your products table and you'll end up losing all of the data. 10 11 00:01:06,050 --> 00:01:12,320 So it's again a dangerous statement to execute and make sure that you check your statement before you 11 12 00:01:12,320 --> 00:01:13,860 hit the run button. 12 13 00:01:15,150 --> 00:01:22,800 And now our products table only has one entry left. But through this process you've seen how we can use 13 14 00:01:23,070 --> 00:01:30,990 the Structured Query Language to Create, Read, Update and Delete data from our SQL table.