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Hi, everyone.

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So in this video, we are going to solve this question, count the occurences of an element.

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So, for example, if this is already so the elements are, let's say, five, five, six, five and

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six, so the value of X is five.

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So how many times five is appearing?

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Seven times second time and third time.

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So five is better than the average three times.

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So output should be three.

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Similarly, if the value of existing so if the value of X is basically six, then six is present one

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time and second time.

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So output should be two.

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Similarly, if the value of X system so ten is not present inside the three, so output should be zero.

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So we can solve this question easily with the help of follow up.

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So what we will do.

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You're simply outraged over the ad, and whenever you see the value, let's take a variable answer.

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Whenever you see the value X, you will answer placeless and you will move ahead.

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Similarly, you will see the value again.

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You will you will again do answer Lespinasse and you will stop when you will reach the end.

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So we just need to maintain a variable answer.

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And whenever we see the X value, I will do answer.

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So let us write the code.

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So I'm not returning anything.

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I will take a variable, so one thing.

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We need to solve this question with the help of equation, and that is obvious there a functional void

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void, a function I will take areas in, but I will take a number of elements I for a rating of Arrietty

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X the value, and we will take this outside variable, we will take this outside variable and we will

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take this variable by reference.

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Initially, the value of this answer will be zero.

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So then we will write the code.

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So whenever we find the value I will do on C++ and initially the value of funds will be zero because

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I will call the function from me and I will pass the answer zero.

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And since I am printing the answer inside me, so I will print my answer inside mean.

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And that's why I need to pass the answer variable by reference.

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So.

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The name of the function is count.

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Count occurences or let's name it, count only, we will take it as input.

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We will take how many elements are there and we will take X, we will take the next time for our trading

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order and we will take on some variable Bio-Reference because we are going to paint the answer inside

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mean.

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So how I will call this function.

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So initially, let's create another variable here and say zero, I will call the function count, I

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will pass any I will pass a number of elements, which is six data, which I want to search for.

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I want to search for five.

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How many times five is appearing, how many times five is appearing in my data, I will start iterating

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from zero and answer variable.

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So this function will update the value of a variable and now we can print the answer here.

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Simple and let's come out.

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So this is count function.

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So here we can just copy this code.

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So if I become too close to him, then I will stop and return, if I is equal to X, then I do not need

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to print anything.

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I will just do answer placeless, so I will do answer placeless and I need to call the government function.

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And I will give answer also, and that is how I think our function will work.

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So let's test for five.

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So five is present one, two and three times.

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So five is three times.

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So arbitrary, arbitrary.

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So I didn't say semicolon.

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So output should be three and tasty, right, output, so let's say I want to search for six, six percent

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two times.

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So this exists two times now let's test for seven, seven is present only one time.

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So seven is one and then is not pleasant inside, there is no output should be zero.

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So I put this zero.

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So our function is working, so this is it from this video, I will see you in the next one.