1 00:00:00,300 --> 00:00:05,220 Hello and welcome to this annual us on which I will show you how to test a transistor rather than on 2 00:00:05,220 --> 00:00:07,320 how to defy its terminals. 3 00:00:07,320 --> 00:00:16,650 This is a transistor as you can see here has three tournaments and we will test it out and see if it's 4 00:00:16,650 --> 00:00:20,500 working or not and identify its tournaments. 5 00:00:20,580 --> 00:00:23,960 As I mentioned earlier this is basically a diode. 6 00:00:23,970 --> 00:00:34,320 So you have to choose but I would reading from here on the watch and or on the digital multimeter and 7 00:00:34,320 --> 00:00:41,700 you then you can watch these terminals the black one and the common and the red one on the one that 8 00:00:41,700 --> 00:00:48,490 has become so diluted I am so blessed to turn it on. 9 00:00:48,630 --> 00:00:59,940 Now we said that the first would be to identify the two terminals that want to give a reading when they're 10 00:01:00,350 --> 00:01:01,170 together. 11 00:01:01,200 --> 00:01:07,770 So if we came here as you can see it must concentrate on this. 12 00:01:07,890 --> 00:01:13,090 So the two terminals that won't give any reading both ways will be the collector and emitter. 13 00:01:13,260 --> 00:01:16,420 So let me test these these first two. 14 00:01:16,560 --> 00:01:17,910 So no reading. 15 00:01:18,900 --> 00:01:32,120 Let me OK with me at the outset Tumblr and k now as you can see we have a reading on that unseated slowly 16 00:01:32,140 --> 00:01:33,230 over the digital multimeter. 17 00:01:33,240 --> 00:01:35,520 So these are love the tool collector and the emitter. 18 00:01:36,040 --> 00:01:37,740 Let's move on to the next two. 19 00:01:37,790 --> 00:01:42,090 So this one on this one we have no reading. 20 00:01:42,110 --> 00:01:49,500 And again this one and this one we have no reading on that it is day one means no reading. 21 00:01:49,910 --> 00:01:54,950 So this one and this one are the collector and emitter. 22 00:01:54,950 --> 00:01:58,430 So this one is the base. 23 00:01:58,580 --> 00:01:59,990 This is the first step. 24 00:02:00,290 --> 00:02:01,250 So let's throw 25 00:02:04,000 --> 00:02:05,530 to let's it to you. 26 00:02:06,650 --> 00:02:07,440 OK. 27 00:02:07,490 --> 00:02:10,760 Let me just focus on this area. 28 00:02:11,090 --> 00:02:14,090 So we have the base identified. 29 00:02:14,090 --> 00:02:21,980 Now we need to know if this base is all this land for us is beyond beyond beyond what we need to do 30 00:02:22,390 --> 00:02:31,170 is simply first knowing that the base will give an image element with both collector and emitter. 31 00:02:31,370 --> 00:02:37,010 So if we connected the positive term out of the base and if it gave reading with these two terminals 32 00:02:37,040 --> 00:02:40,070 it means that positive means and beyond. 33 00:02:40,220 --> 00:02:42,310 So it will be an unbeaten transistor. 34 00:02:42,830 --> 00:02:45,400 If it doesn't give a reading we will have to reverse it. 35 00:02:45,410 --> 00:02:50,000 We have to contain the negative been here to the base. 36 00:02:50,180 --> 00:02:56,880 And if it give a reading this means that the base is negative or on which means that this is be unbeatable 37 00:02:56,910 --> 00:02:57,470 in the store. 38 00:02:57,960 --> 00:02:58,850 So of start 39 00:03:01,310 --> 00:03:06,520 this is the most if they're not connected to the base and it's connected to this terminal. 40 00:03:06,680 --> 00:03:09,240 It gave readings and density as you can see here. 41 00:03:09,560 --> 00:03:12,740 If you connect it to the other bend but also give a reading. 42 00:03:13,580 --> 00:03:15,780 So this is the base. 43 00:03:15,920 --> 00:03:17,190 It's connected. 44 00:03:17,190 --> 00:03:18,540 The red blob. 45 00:03:18,590 --> 00:03:22,160 This means that it's and beyond transistor. 46 00:03:22,250 --> 00:03:28,060 So and B on the transistor This is the Times on the. 47 00:03:28,550 --> 00:03:33,860 Now the final step which is I didn't find the collector and emitter between these two bands. 48 00:03:34,070 --> 00:03:39,740 Now as I mentioned earlier that one that will give higher measurement when connected to the base will 49 00:03:39,740 --> 00:03:40,400 be the emitter. 50 00:03:40,580 --> 00:03:45,200 So let's connect the positive terminal to the base. 51 00:03:45,260 --> 00:03:48,170 Let's connect this to the spin. 52 00:03:48,350 --> 00:03:51,820 Gave us six hundred seventy five. 53 00:03:51,860 --> 00:03:57,860 It's going to spin six hundred and eighty nine. 54 00:03:57,860 --> 00:04:04,610 So this one has a higher reading which is that this terminal as I mentioned earlier the one that will 55 00:04:04,610 --> 00:04:07,800 give higher leading with the base will be the emitter. 56 00:04:07,790 --> 00:04:14,190 So now we have this as the emitter and the last one is the correct. 57 00:04:14,270 --> 00:04:16,300 So this is our transistor. 58 00:04:16,370 --> 00:04:17,710 It's fully functional. 59 00:04:18,020 --> 00:04:18,970 It's working. 60 00:04:19,040 --> 00:04:22,970 And we did found out that it's.