1
00:00:00,150 --> 00:00:10,170
Now, after this, we create another dictionary, Alpha two, which is also equal to some values, but

2
00:00:10,170 --> 00:00:12,320
now here we are changing it.

3
00:00:12,690 --> 00:00:16,040
We are reversing the order or shuffling the order.

4
00:00:16,050 --> 00:00:23,760
Basically, you can see so say, for example, reticular the key code first and here we give that is

5
00:00:23,760 --> 00:00:43,410
equal to, say, Z, then let's give one as equal to say then say two equal to see B, then three equal

6
00:00:43,410 --> 00:01:09,450
to C for equal to the five equal to E, move on to the next line say six as F seven as G then eight

7
00:01:12,930 --> 00:01:17,430
eight nine I.

8
00:01:18,810 --> 00:01:26,100
Then you have been as G you have 11,

9
00:01:29,280 --> 00:01:42,730
12 and 13 and 14 as say and.

10
00:01:43,770 --> 00:02:08,310
Then 15th or the next line, C 16 as B, 17 as Q, 18 as R 19 is.

11
00:02:10,700 --> 00:02:21,310
20 as deep and going to the last line, see you 22.

12
00:02:22,630 --> 00:02:25,250
We do any three.

13
00:02:26,720 --> 00:02:36,470
W twenty four X and twenty five Y.

14
00:02:37,530 --> 00:02:42,470
So we have shuffled certain characters, your correspondent, to the index as after shift.

15
00:02:43,080 --> 00:02:49,500
Now, once we have done with this, we will be creating the functions to accept the string, OK, according

16
00:02:49,500 --> 00:02:51,940
to the shift that you are providing.

17
00:02:52,200 --> 00:02:54,450
So we will define how function see

18
00:02:57,240 --> 00:03:08,730
encrypt the text, which will take the message to start and shift or features two parameters.

19
00:03:09,000 --> 00:03:13,830
And in this will be the ciphertext as initially blank.

20
00:03:14,400 --> 00:03:22,540
We will run a loop for later SDR in your message SDR.

21
00:03:23,250 --> 00:03:26,030
And for that we will check your first basis.

22
00:03:26,490 --> 00:03:36,570
That is, if we will check the letter is still not equal to a blank space, then we will look up the

23
00:03:36,570 --> 00:03:44,220
dictionary and we will add the shift to the index and we will take no one that's equal to use your dictionary

24
00:03:44,220 --> 00:03:48,870
Alpha1 in the index as little as SDR.

25
00:03:49,710 --> 00:03:56,490
Plus use the shift code that you have passed modulus twenty six.

26
00:03:56,750 --> 00:04:01,860
Now that Hillary will look up the second dictionary for the shift alphabets and then we will add a bit.

27
00:04:02,310 --> 00:04:05,880
So we will take your ciphertext.

28
00:04:06,450 --> 00:04:16,140
Plus is equal to the second dictionary that is Alpha to add the index number.

29
00:04:17,100 --> 00:04:25,490
Now, if it is not having any spaces, go to the spot on your we will add the space, my giving cipher

30
00:04:25,680 --> 00:04:29,610
text plus is equal to adult space there.

31
00:04:30,150 --> 00:04:33,510
And once we have done that, let's move.

32
00:04:34,740 --> 00:04:41,940
For in the for loop and we Silvertone the value of Saiful, which means our definition of the function

33
00:04:42,090 --> 00:04:44,580
in cryptics is completed.

34
00:04:44,970 --> 00:04:51,590
Now we will have another function here that is see the clip fixed.

35
00:04:51,810 --> 00:04:59,110
And this also takes your message, Istar and shift your parameters.

36
00:04:59,400 --> 00:05:05,870
And here we have the ciphertext, which is equal to initially black.

37
00:05:06,450 --> 00:05:08,070
Then again, here we run.

38
00:05:08,370 --> 00:05:12,780
So let us start in your messages, dear.

39
00:05:13,350 --> 00:05:17,240
And in this four loop, we will check for the spaces.

40
00:05:17,610 --> 00:05:25,960
That is, if your letter is still not equal to space, call it.

41
00:05:26,070 --> 00:05:30,550
And then we will look up the dictionary and subtract the shift to the index.

42
00:05:30,880 --> 00:05:39,960
So we'll take no one is equal to we will use the dictionary alpha one in the index of letter SDR.

43
00:05:41,310 --> 00:05:52,650
That's minus we use the shift code plus twenty six modulus twenty six and then we will look up for the

44
00:05:52,770 --> 00:05:55,860
second dictionary and for the alphabet.

45
00:05:56,130 --> 00:06:00,090
So here we'll use the full text.

46
00:06:00,690 --> 00:06:07,770
Plus is equal to your dictionary alpha to add the index of number.

47
00:06:08,880 --> 00:06:16,710
Now if this is not true we will go for the ls part here and again we will add the next thing.

48
00:06:16,710 --> 00:06:21,350
The ciphertext plus is equal to space.

49
00:06:21,930 --> 00:06:31,200
So once we have added this, we are supposed to also return the value of the cipher text.

50
00:06:31,800 --> 00:06:39,480
And once that is done, we will define here another main function, which basically is helpful for running

51
00:06:39,480 --> 00:06:40,260
our program.

52
00:06:40,710 --> 00:06:45,960
Now here we are going to use the upper function to convert the lowercase characters to uppercase.

53
00:06:46,290 --> 00:06:54,700
So we are going to use here your message SDR and we will pass that on message as C let's give here in

54
00:06:54,730 --> 00:07:06,060
capital C 510 hiking with seasonal Saiful as a text and double quotation marks.

55
00:07:06,480 --> 00:07:16,050
Also, we give the value of shift code as equal to thirty and then we say here the result SDR is equal

56
00:07:16,050 --> 00:07:20,790
to we call here and grep text in bracket.

57
00:07:21,930 --> 00:07:30,780
Same message as the R dot convert to upper and use the value of shift code.

58
00:07:31,650 --> 00:07:38,600
Then finally you print the value of result SDR here.

59
00:07:39,150 --> 00:07:50,970
Now to execute this main matter, what will have to do is check your if c your name is equal to your

60
00:07:51,450 --> 00:07:57,510
mean in single quotation marks, then you want to call the main method.

61
00:07:58,050 --> 00:07:59,490
Now let us save this.

62
00:08:00,060 --> 00:08:05,760
Let's save it again in the python hacking big enough Sidmouth seven VI.

63
00:08:06,790 --> 00:08:09,210
And let us try to run the audio.

64
00:08:09,700 --> 00:08:15,480
So this is how we are getting the encrypted one, but now suppose we want also for decrypting it.

65
00:08:15,700 --> 00:08:18,580
So we copied on this text go back here.

66
00:08:19,000 --> 00:08:23,800
And in the same main method, we see another same message.

67
00:08:23,800 --> 00:08:27,720
Asgeir is equal to the text that we have copied down.

68
00:08:27,730 --> 00:08:37,390
Now we have this shift code as again, 13 we have again, the result are now we are calling the decrypt

69
00:08:37,750 --> 00:08:40,330
text matau passing there again.

70
00:08:40,330 --> 00:08:51,580
The messages are not in uppercase and the value of shift code and then printing the value of result

71
00:08:51,700 --> 00:08:52,670
SDR here.

72
00:08:53,410 --> 00:08:59,130
OK, so now again, let us save this and go back for executing.

73
00:08:59,830 --> 00:09:00,720
OK, fine.

74
00:09:00,910 --> 00:09:01,900
Let's check here

75
00:09:04,900 --> 00:09:09,220
we are having the values decrypt fixed.

76
00:09:09,850 --> 00:09:12,970
So the ciphertext.

77
00:09:14,100 --> 00:09:16,290
We must have made some spelling mistakes.

78
00:09:16,890 --> 00:09:17,910
Let's check it.

79
00:09:21,970 --> 00:09:27,470
OK, so better be copied on one call and see the output now.

80
00:09:28,810 --> 00:09:31,210
An invention has to be also proper.

81
00:09:31,840 --> 00:09:38,770
So getting this now, if you want to know how basically it is getting hacked, if you see the first

82
00:09:38,770 --> 00:09:45,980
character as we come back to our program here, what is the value of the index of the overfield?

83
00:09:46,120 --> 00:09:49,320
You can just find out that is 60.

84
00:09:49,750 --> 00:09:55,850
If you add 16 plus 13, you get the value as twenty nine.

85
00:09:56,920 --> 00:10:04,090
Now, when the value go about that will also require a calculator just to make you understand how you

86
00:10:04,390 --> 00:10:09,140
see the value initially that we have given, therefore the character is.

87
00:10:09,880 --> 00:10:18,500
So the value if you see here for B in the first one coming at 16, if we take your C 16 plus the picture

88
00:10:18,520 --> 00:10:21,490
that we have given is 13, it becomes twenty six.

89
00:10:21,490 --> 00:10:24,580
If we subtract twenty six from that, the value comes to three.

90
00:10:25,060 --> 00:10:29,020
So what is the index at the second dictionary for three.

91
00:10:29,290 --> 00:10:30,140
That is C.

92
00:10:30,520 --> 00:10:32,680
So is that coming as the first character.

93
00:10:32,710 --> 00:10:33,250
Yes.

94
00:10:33,730 --> 00:10:35,130
Let's try it for another.

95
00:10:35,140 --> 00:10:36,640
See the value of life.

96
00:10:37,060 --> 00:10:38,680
Go to the first dictionary.

97
00:10:38,710 --> 00:10:41,460
What is the index for y given us twenty five.

98
00:10:41,830 --> 00:10:49,350
If we go back here and see twenty five plus the code thirteen comes to thirty eight.

99
00:10:49,900 --> 00:10:52,560
If we subtract twenty six we get twelve.

100
00:10:52,930 --> 00:10:54,310
What's the value coming on.

101
00:10:54,310 --> 00:10:54,760
Twelve.

102
00:10:54,760 --> 00:10:56,930
That is it in the second dictionary.

103
00:10:57,040 --> 00:10:57,440
Right.

104
00:10:57,760 --> 00:11:00,520
So is that coming here for L.

105
00:11:00,550 --> 00:11:01,110
Yes.

106
00:11:02,380 --> 00:11:08,650
So that is how you're getting a substitute for every key from the force to dictionary.

107
00:11:08,650 --> 00:11:15,130
Alpha1 being substituted by the second dictionary for two and that is the value you're getting for a

108
00:11:15,130 --> 00:11:16,270
decrepit text.

109
00:11:17,140 --> 00:11:24,370
Similarly, if you go from decrypted to encrypted the value of the dictionary, Alfond two is being

110
00:11:24,370 --> 00:11:29,620
substituted in dictionary Alpha1 and then you get the encrypted fixed.

111
00:11:29,950 --> 00:11:32,580
This is basically how you'll see the cipher is executing.

112
00:11:32,590 --> 00:11:36,490
So we have not used your Cichon or the AWADI function.

113
00:11:36,490 --> 00:11:43,240
Instead, we have created the dictionary Alpha one and two by giving some individual values and the

114
00:11:43,240 --> 00:11:50,560
key code for every character and we're using that for encrypting it and again for decrypting the particular

115
00:11:50,560 --> 00:11:51,700
given text.

116
00:11:51,730 --> 00:11:57,800
OK, so in this way we have seen multiple examples on SISA Cipher.

117
00:11:58,100 --> 00:12:02,530
OK, we should make the concept of how to encrypt decrypt using.

118
00:12:02,530 --> 00:12:05,230
This is a cipher concept very much clear.

119
00:12:05,650 --> 00:12:06,000
Right.

120
00:12:06,220 --> 00:12:10,970
So that's it from this particular session of the cipher in Python Hacking.

121
00:12:11,620 --> 00:12:12,490
Thank you very much.