WEBVTT

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 Hello and welcome this video which
 is another in the series of videos

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 on the CCNA exam assessment.

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 In this assessment we're going to be
 assessing you on IP before addressing

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 and subnetting. So let's
 get right to it.

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 Question number one.

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 When using the original method of class
 full IP addressing, what class

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 of network does the address
 of 126.3.45.1 fall into?

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 That is a class A address.

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 Question two. When using the original
 method of class full IP addressing,

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 what class of network does the
 address 225.6.76.3 fall into?

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 Hopefully you answered
 D, a class D address.

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 Question three. When using the original
 class full method of IP addressing,

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 which of the following answers displays
 the full range of class B addresses?

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 The correct answer is D, 128
.000 through 199.255.255.

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 Question four. Which of the following
 IP before addresses displayed in

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 binary falls into the
 class C address space?

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 Hopefully answered B and the way you
 identify that is class C addresses

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 begin in binary with
 the pattern of 110.

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 And B is the only answer that
 begins with 110 in binary.

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 Question five. PCA contains the IP
 before address and mask of 134.55.6

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.18. Given this information, what is
 the maximum quantity of remaining

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 hosts that could reside
 in this same subnet?

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 The correct answer is B, 13 hosts.


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 Now remember, you might have been stumped
 by this and thought, oh, well,

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 with the slash 28, that means there's
 a total of 16 addresses.

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 But when we extract from that, the network
 address and the broadcast address,

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 that gives us 14 addresses.

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 So why isn't C the correct answer?


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 Well, because remember, one of those
 addresses has already been allocated

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 to PCA. And the question is, what is
 the maximum quantity of remaining

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 hosts? So once you factor in the PCA has
 already used one of those available

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 addresses of the 14, that means
 there's only 13 remaining.

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 Question six. Which of the following
 pairs of hosts reside within the

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 same IPB4 subnet?

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 The correct answer is D.

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 Now just as a side note here, remember
 that I said at the very beginning

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 of this course that the intention of
 this series is not to review and

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 go over all the topics
 of the CCNA.

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 If you do find yourself missing some
 of these questions, whether it be

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 on IPB4 addressing and subnetting or
 anything else, please use this as

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 an opportunity to go back to some of
 the other video series within INE's

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 CCNA learning path and refresh
 yourself on those topics.

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 We don't have time during this course
 to review everything that I've already

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 covered in other video series.

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 Question seven. With regards to the address
 of 134.44.1.95 slash 27, which

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 of the following answers is correct
 and select two answers?

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 The correct answer is A, this is a
 broadcast address and D, there are

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 30 available hosts
 in this address.

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 Question eight. A company is given the
 network of 156.10.00.255.255.00.

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 From their internet
 service provider.

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 Internally, they decide to subnet this
 network with each new subnet having

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 a mask of 255.255.248.0.

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 Given this information, what is the maximum
 quantity of subnets that will

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 be available for them to use?

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 Let's see, 248. Let's actually
 just do this real quick.

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 248 is 12345678.

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 So that's an additional
 of five bits.

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 So if we just do two to the power of five,
 now always like to do the finger

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 method, this is what I've done in
 my classes, two networks, 481632.

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 So that gives you your answer of 32
 possible subnets by stealing five

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 extra bits. Question number nine.

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 An enterprise customer is given a network
 from their ISP, which includes

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 a mask of 255.255.255.0.

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 The customer has a total
 of 22 internal networks.

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 When subnetting, what new net mask
 would provide the greatest quantity

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 of hosts per network and yet still give
 the customer at least 22 subnets?

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 The correct answer here is B.

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 255.255.248. The key thing that you had
 to pay attention to here is would

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 provide the greatest quantity
 of hosts per network.

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 So certainly you could have stolen
 a lot more bits than that and given

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 yourself far more than 22
 networks that you needed.

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 But if you had done that, each network
 would have had fewer hosts.

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 So the greatest quantity of hosts and
 yet still give yourself 22 networks

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 would have to be this network
 mask right here.

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 Any other network mask available in
 these answers would either not give

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 you 22 networks or it would give you
 more than 22 networks, but at the

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 expense of the quantity of hosts
 within those networks.

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 Question ten. Which RFC specifies the IPv4
 address ranges that are considered

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 private addresses?

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 And that would be RFC 1918,
 which is answer A.

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 RFC 791, which is answer D, is the original
 RFC for IP, but not for private

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 IP addresses. Question eleven.

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 Which of the following IPv4 addresses
 would be considered a public globally

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 routable unicast address?

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 And the answer is C.

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 All of those other addresses that you
 see there are in the private range

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 of addresses. But in the private range
 of the 172, it's 172.16 up to 172

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.31. So 172.32 begins our next
 range of public addresses.

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 172.32 does. Question twelve.

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 Which of the following answers provides
 an alternative way to express

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 the subnet mask of 255.255.240.0?

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 And the answer is slash 20.

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 Question thirteen.

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 Question thirteen.

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 Your company has obtained the network
 of 176.10.00 slash 16 from an ISP.

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 You need to subnet this network and
 your largest subnet will contain 100

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 host devices. Which of the following
 answers provides a subnet work that

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 will fit your largest subnet, while
 at the same time consuming the least

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 possible quantity of the network.

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 And the answer is A.

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 Remember the way we did this here is
 that if your largest subnet needs

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 to have 100 host devices, once again
 we can do the old finger method.

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 So if we steal one bit, that gives
 us 2 minus 2, which is zero.

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 Remember it's always number of bits,
 number of host bits minus 2.

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 So 2 to the power of 1 is 2, minus
 2 is zero so that we don't have any

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 hosts. If we steal two hosts, then that
 gives us 4 and we'll just subtract

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 the 2 at the later date.

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 So 4, 8, 16, 32, 64, 128.

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 So if we take 6 bits, if we add 6 bits
 of hosts, no, 7, if we have 7 bits

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 of hosts, on the end, those 7 bits
 of hosts will give us 128 minus 2.

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 So 126 hosts. So if we think about
 that, if we have 7 bits on the end,

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 that means in our last octet, we have
 a networking bit, but then all the

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 other bits are host bits.

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 I'm not going to do
 that all the way.

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 So that means we'd have 24 bits
 of network plus this one here.

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 So that's a slash 25.

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 It gives us 7 hosts bits and a slash
 25 is equivalent to 255, 255, 255

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.128. Question 14.

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 IPv4 addresses are becoming a scarce
 resource as they are rapidly being

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 depleted. Which of the following features
 or protocols was designed to

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 help extend the life
 of IP version 4?

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 And that would be B, NAT, or
 network address translation.

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 Question 15. Pair the correct default
 mask value with its appropriate

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 class of network.

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 And here is your answer.

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 Multicast does not use subnet masks,
 so that is not applicable.

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 Question 16. Your ISP gives you
 the network of 144.12.12.0.

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 You need to divide this
 into 22 subnetworx.

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 Using the same length subnetting method
 and allowing for subnet zero,

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 which is 144.12.12.0, to be your first
 subnet, what will be the address

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 of your sixth subnet?

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 And the answer is D.

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 So once again, if we use what I like
 to call the finger method here, if

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 we need 22 subnetworx, if we steal one
 bit, that gives us two networks.

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 Two bits gives us four,
 eight, 16, 32.

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 So we need to steal a minimum of five
 bits from our host, adding them

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 to the networks in order to give
 us at least 32 networks.

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 And right now we need
 22, that's five bits.

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 So we start out with a slash 24.

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 So that's network,
 network, network.

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 So each of those first octets.

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 And now of our last
 byte, there we go.

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 12345678, I think I may have a little
 bit too much, two, three, four,

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 five, six, seven, eight.

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 Yes, I do. Let's get rid
 of that one right there.

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 Okay, so we said we need
 to steal five bits.

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 So that means our dividing line between
 network and host is right here.

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 So when you ask yourself, okay, so
 my first network is going to be the

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 zero network. We already
 said that subnet zero.

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 So that's going to be our starting
 network of 144.1212, zero.

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 Then you ask yourself, what is the
 value of this bit right there?

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 Well, that is the one, two, four.

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 That is the eight bit.

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 So that means every network starting
 with the second network on up is

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 going to be some multiple
 or integral of eight.

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 They're all going to
 be integers of eight.

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 So the first network is zero.

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 The second network is eight, 16.

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 And what are we looking for?

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 We're looking for
 the sixth network.

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 So zero, eight, 16,
 24, 32, and 40.

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 So that's why the correct
 answer is D.

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 144, 12, 12, dot 40.

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 Question 17. What is the sub network
 address of the following host?

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 And you see the host address
 and mass right there.

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 The subnet or network address that
 that host lives in is answer A.

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 The 125 dot 22 dot
 76 dot 48 network.

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 And the final octet, the 32 bit
 and the 16 bit are turned on.

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 And those are all the networking
 bits you have in that final byte.

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 So 32 and 16 gives you 48.

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 Question 18. Pair the IPv4 addresses
 with their correct description.

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 And here's your answer.

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 The first one, 169 dot 254, that is
 an automatic private IP address.

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 127 dot anything, but specifically 127
 dot 001 is the loopback address.

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 Any address that's 224 on up to
 239 is a multicast address.

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 And 172 16 falls within our
 range of private addresses.

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 Question 19. Which of the following
 commands could you use within the

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 Microsoft Windows operating system to
 view the IP address, default gateway

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 and DNS server assigned
 to a device?

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 And the correct answer is IP
 config forward slash all.

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 You need that forward slash all in order
 to see the DNS server information.

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 Question 20. What command was used on
 a laptop running Microsoft Windows

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 10 or Microsoft Windows OS, the operating
 system, in order to obtain the

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 output that is shown here.

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 And that command was
 netstat minus Rn.

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 Question 21. What command was used on
 a Macbook running Mac OS, otherwise

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 known as OSX, in order to obtain
 the output shown here.

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 And that command was IF config.

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 And that completes this video for
 our CCNA assessment review.